Pentcho Valev
2023-08-09 16:25:16 UTC
Richard Feynman: "First, let us calculate the time required for the light to go from B to E and back. Let us say that the time for light to go from plate B to mirror E is t_1, and the time for the return is t_2. Now, while the light is on its way from B to the mirror, the apparatus moves a distance ut_1, so the light must traverse a distance L + ut_1, at the speed c. We can also express this distance as ct_1, so we have
ct_1 = L+ut_1, or t_1 = L/(c−u).
(This result is also obvious from the point of view that the velocity of light relative to the apparatus is c−u, so the time is the length L divided by c−u.)" http://www.feynmanlectures.caltech.edu/I_15.html
Feynman's words "at the speed c" express the assumption that the speed of light is independent of the speed of the emitter (in this case the apparatus moving along the Earth's orbit). And, as Feynman explains, the assumption entails the absurdity that "the velocity of light relative to the apparatus is c−u". So the assumption is obviously false, isn't it? That is the reason why the final prediction based on this assumption is incompatible with the null result of the Michelson-Morley experiment.
If, instead of "at the speed c", we have a new assumption,
"at the speed c ± u",
as predicted by Newton's theory, the calculation (based on the new assumption) will give a new prediction,
t_1 + t_2 = 2t_3 = 2L/c,
which exactly matches the null result of the Michelson-Morley experiment.
Pentcho Valev https://twitter.com/pentcho_valev
ct_1 = L+ut_1, or t_1 = L/(c−u).
(This result is also obvious from the point of view that the velocity of light relative to the apparatus is c−u, so the time is the length L divided by c−u.)" http://www.feynmanlectures.caltech.edu/I_15.html
Feynman's words "at the speed c" express the assumption that the speed of light is independent of the speed of the emitter (in this case the apparatus moving along the Earth's orbit). And, as Feynman explains, the assumption entails the absurdity that "the velocity of light relative to the apparatus is c−u". So the assumption is obviously false, isn't it? That is the reason why the final prediction based on this assumption is incompatible with the null result of the Michelson-Morley experiment.
If, instead of "at the speed c", we have a new assumption,
"at the speed c ± u",
as predicted by Newton's theory, the calculation (based on the new assumption) will give a new prediction,
t_1 + t_2 = 2t_3 = 2L/c,
which exactly matches the null result of the Michelson-Morley experiment.
Pentcho Valev https://twitter.com/pentcho_valev